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4x^2-113x+603=0
a = 4; b = -113; c = +603;
Δ = b2-4ac
Δ = -1132-4·4·603
Δ = 3121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-113)-\sqrt{3121}}{2*4}=\frac{113-\sqrt{3121}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-113)+\sqrt{3121}}{2*4}=\frac{113+\sqrt{3121}}{8} $
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